24x=3x^2+48

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Solution for 24x=3x^2+48 equation: 



24x=3x^2+48

We move all terms to the left:

24x-(3x^2+48)=0

We get rid of parentheses

-3x^2+24x-48=0

a = -3; b = 24; c = -48;
Δ = b2-4ac
Δ = 242-4·(-3)·(-48)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-24}{-6}=+4$

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